A science journalist writes that a virus spreads such that each infected person infects 1.8 others every 3 days. Starting with 5 cases, how many total infections occur by day 9 (assume geometric progression)? - NBX Soluciones

Understanding the Context

The R₀ (basic reproduction number) of 1.8 implies that, on average, each infected person infects 1.8 new individuals during a 3-day cycle. Unlike static infections, this transmission rate fuels rapid, compound growth in cumulative case numbers. This is especially relevant in metropolitan areas or dense social networks where contact rates remain high.

The Geometric Progression of Infection

Science journalists increasingly rely on mathematical modeling to communicate outbreak dynamics clearly to the public. Here’s how the spread unfolds over day 9, assuming a 3-day interval:

• Day 0 (Start): 5 cases
  
• Day 3: Each of 5 people infects 1.8 others → 5 × 1.8 = 9 new cases. Total = 5 + 9 = 14
  
• Day 6: Each of 9 new cases → 9 × 1.8 = 16.2 ≈ 16 new infections. Cumulative = 14 + 16 = 30
  
• Day 9: Each of those 16 infects 1.8 → 16 × 1.8 = 28.8 ≈ 29 new cases. Cumulative total = 30 + 29 = 59

Key Insights

However, to maintain precision and reflect cumulative infections over each 3-day period (including day 0 to day 9), we sum the geometric series directly:

Total infections over 9 days follow
Sₙ = a × (1 – rⁿ) / (1 – r)
Where:

• a = 5 (initial cases)
  
• r = 1.8 (reproduction factor every 3 days)
  
• n = 3 periods (days 0 → 3 → 6 → 9)

Plugging in:
S₃ = 5 × (1 – 1.8³) / (1 – 1.8)
1.8³ = 5.832 → S₃ = 5 × (1 – 5.832) / (–0.8)
S₃ = 5 × (–4.832) / (–0.8)
S₃ = 5 × 6.04 = 30.2

Wait—this represents cumulative new infections only. But the total infections including the original cases is:
S₃ = 5 (initial) + 30.2 (new) = ≈30.2 total cumulative infections by day 9, but this undercounts if new infections continue additive.

But note: The geometric series formula Sₙ = a(1−rⁿ)/(1−r) calculates the sum of all infections generated across n generations, assuming each infected person spreads in the next phase.

Final Thoughts

Thus, cumulative infections from initial 5 through day 9, with spreading every 3 days and exponential growth, total approximately:

Total infections ≈ 59 (rounded to nearest whole number based on 5 + 9 + 16 + 29 = 59)

This reflects:

• Day 0 to 3: 5 × 1.8 = 9 new
  
• Day 3 to 6: 9 × 1.8 = 16.2 ≈ 16 new
  
• Day 6 to 9: 16 × 1.8 = 28.8 ≈ 29 new
  Cumulative: 5 + 9 + 16 + 29 = 59

Why This Insight Matters

Modeling viral spread using geometric progression empowers both scientists and the public to grasp outbreak dynamics. The 1.8 R value signals sustained transmission, but knowing how infections grow helps target interventions—such as testing, isolation, and vaccination—before healthcare systems become overwhelmed.

Final Summary