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\boxed{\frac135} - NBX Soluciones

📅 May 3, 2026 👤 scraface

May 03, 2026

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📌 Solve first system:

📌 From \(a + 2b = 4\), \(a = 4 - 2b\). Plug into \(3a - b = 5\):

📌 3(4 - 2b) - b = 12 - 6b - b = 12 - 7b = 5 \Rightarrow 7b = 7 \Rightarrow b = 1 \Rightarrow a = 2

📌 Second system: \(c + 2d = 1\), \(3c - d = -2\)

📌 From \(c = 1 - 2d\), plug:

📌 3(1 - 2d) - d = 3 - 6d - d = 3 - 7d = -2 \Rightarrow 7d = 5 \Rightarrow d = rac{5}{7},\ c = 1 - rac{10}{7} = -rac{3}{7}

📌 \mathbf{M} = egin{bmatrix} 2 & 1 \ -rac{3}{7} & rac{5}{7} \end{bmatrix}

📌 oxed{egin{bmatrix} 2 & 1 \ -\dfrac{3}{7} & \dfrac{5}{7} \end{bmatrix}}

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